Optimal. Leaf size=169 \[ \frac{16 a^2 (21 A+13 C) \tan (c+d x) \sqrt{a \sec (c+d x)+a}}{315 d}+\frac{64 a^3 (21 A+13 C) \tan (c+d x)}{315 d \sqrt{a \sec (c+d x)+a}}+\frac{2 a (21 A+13 C) \tan (c+d x) (a \sec (c+d x)+a)^{3/2}}{105 d}+\frac{2 C \tan (c+d x) (a \sec (c+d x)+a)^{7/2}}{9 a d}-\frac{4 C \tan (c+d x) (a \sec (c+d x)+a)^{5/2}}{63 d} \]
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Rubi [A] time = 0.316348, antiderivative size = 169, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.121, Rules used = {4083, 4001, 3793, 3792} \[ \frac{16 a^2 (21 A+13 C) \tan (c+d x) \sqrt{a \sec (c+d x)+a}}{315 d}+\frac{64 a^3 (21 A+13 C) \tan (c+d x)}{315 d \sqrt{a \sec (c+d x)+a}}+\frac{2 a (21 A+13 C) \tan (c+d x) (a \sec (c+d x)+a)^{3/2}}{105 d}+\frac{2 C \tan (c+d x) (a \sec (c+d x)+a)^{7/2}}{9 a d}-\frac{4 C \tan (c+d x) (a \sec (c+d x)+a)^{5/2}}{63 d} \]
Antiderivative was successfully verified.
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Rule 4083
Rule 4001
Rule 3793
Rule 3792
Rubi steps
\begin{align*} \int \sec (c+d x) (a+a \sec (c+d x))^{5/2} \left (A+C \sec ^2(c+d x)\right ) \, dx &=\frac{2 C (a+a \sec (c+d x))^{7/2} \tan (c+d x)}{9 a d}+\frac{2 \int \sec (c+d x) (a+a \sec (c+d x))^{5/2} \left (\frac{1}{2} a (9 A+7 C)-a C \sec (c+d x)\right ) \, dx}{9 a}\\ &=-\frac{4 C (a+a \sec (c+d x))^{5/2} \tan (c+d x)}{63 d}+\frac{2 C (a+a \sec (c+d x))^{7/2} \tan (c+d x)}{9 a d}+\frac{1}{21} (21 A+13 C) \int \sec (c+d x) (a+a \sec (c+d x))^{5/2} \, dx\\ &=\frac{2 a (21 A+13 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{105 d}-\frac{4 C (a+a \sec (c+d x))^{5/2} \tan (c+d x)}{63 d}+\frac{2 C (a+a \sec (c+d x))^{7/2} \tan (c+d x)}{9 a d}+\frac{1}{105} (8 a (21 A+13 C)) \int \sec (c+d x) (a+a \sec (c+d x))^{3/2} \, dx\\ &=\frac{16 a^2 (21 A+13 C) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{315 d}+\frac{2 a (21 A+13 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{105 d}-\frac{4 C (a+a \sec (c+d x))^{5/2} \tan (c+d x)}{63 d}+\frac{2 C (a+a \sec (c+d x))^{7/2} \tan (c+d x)}{9 a d}+\frac{1}{315} \left (32 a^2 (21 A+13 C)\right ) \int \sec (c+d x) \sqrt{a+a \sec (c+d x)} \, dx\\ &=\frac{64 a^3 (21 A+13 C) \tan (c+d x)}{315 d \sqrt{a+a \sec (c+d x)}}+\frac{16 a^2 (21 A+13 C) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{315 d}+\frac{2 a (21 A+13 C) (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{105 d}-\frac{4 C (a+a \sec (c+d x))^{5/2} \tan (c+d x)}{63 d}+\frac{2 C (a+a \sec (c+d x))^{7/2} \tan (c+d x)}{9 a d}\\ \end{align*}
Mathematica [A] time = 1.39697, size = 125, normalized size = 0.74 \[ \frac{a^2 \tan \left (\frac{1}{2} (c+d x)\right ) \sec ^4(c+d x) \sqrt{a (\sec (c+d x)+1)} (4 (441 A+698 C) \cos (c+d x)+4 (966 A+803 C) \cos (2 (c+d x))+588 A \cos (3 (c+d x))+903 A \cos (4 (c+d x))+2961 A+584 C \cos (3 (c+d x))+584 C \cos (4 (c+d x))+2908 C)}{1260 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.287, size = 132, normalized size = 0.8 \begin{align*} -{\frac{2\,{a}^{2} \left ( -1+\cos \left ( dx+c \right ) \right ) \left ( 903\,A \left ( \cos \left ( dx+c \right ) \right ) ^{4}+584\,C \left ( \cos \left ( dx+c \right ) \right ) ^{4}+294\,A \left ( \cos \left ( dx+c \right ) \right ) ^{3}+292\,C \left ( \cos \left ( dx+c \right ) \right ) ^{3}+63\,A \left ( \cos \left ( dx+c \right ) \right ) ^{2}+219\,C \left ( \cos \left ( dx+c \right ) \right ) ^{2}+130\,C\cos \left ( dx+c \right ) +35\,C \right ) }{315\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}\sin \left ( dx+c \right ) }\sqrt{{\frac{a \left ( \cos \left ( dx+c \right ) +1 \right ) }{\cos \left ( dx+c \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.507498, size = 333, normalized size = 1.97 \begin{align*} \frac{2 \,{\left ({\left (903 \, A + 584 \, C\right )} a^{2} \cos \left (d x + c\right )^{4} + 2 \,{\left (147 \, A + 146 \, C\right )} a^{2} \cos \left (d x + c\right )^{3} + 3 \,{\left (21 \, A + 73 \, C\right )} a^{2} \cos \left (d x + c\right )^{2} + 130 \, C a^{2} \cos \left (d x + c\right ) + 35 \, C a^{2}\right )} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{315 \,{\left (d \cos \left (d x + c\right )^{5} + d \cos \left (d x + c\right )^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 5.18204, size = 362, normalized size = 2.14 \begin{align*} \frac{8 \,{\left (315 \, \sqrt{2} A a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 315 \, \sqrt{2} C a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) -{\left (1050 \, \sqrt{2} A a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 630 \, \sqrt{2} C a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) -{\left (1323 \, \sqrt{2} A a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 819 \, \sqrt{2} C a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) - 4 \,{\left (189 \, \sqrt{2} A a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 117 \, \sqrt{2} C a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) - 2 \,{\left (21 \, \sqrt{2} A a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right ) + 13 \, \sqrt{2} C a^{7} \mathrm{sgn}\left (\cos \left (d x + c\right )\right )\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{315 \,{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - a\right )}^{4} \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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